4(x+2)=4(2x+3)+4x

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Solution for 4(x+2)=4(2x+3)+4x equation: 



4(x+2)=4(2x+3)+4x

We move all terms to the left:

4(x+2)-(4(2x+3)+4x)=0

We multiply parentheses

4x-(4(2x+3)+4x)+8=0



We calculate terms in parentheses: -(4(2x+3)+4x), so:

4(2x+3)+4x

We add all the numbers together, and all the variables

4x+4(2x+3)

We multiply parentheses

4x+8x+12

We add all the numbers together, and all the variables

12x+12

Back to the equation:

-(12x+12)



We get rid of parentheses

4x-12x-12+8=0

We add all the numbers together, and all the variables

-8x-4=0

We move all terms containing x to the left, all other terms to the right

-8x=4

x=4/-8

x=-1/2

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