4(x+2)=5-2(x-3)

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Solution for 4(x+2)=5-2(x-3) equation: 



4(x+2)=5-2(x-3)

We move all terms to the left:

4(x+2)-(5-2(x-3))=0

We multiply parentheses

4x-(5-2(x-3))+8=0



We calculate terms in parentheses: -(5-2(x-3)), so:

5-2(x-3)

determiningTheFunctionDomain
-2(x-3)+5

We multiply parentheses

-2x+6+5

We add all the numbers together, and all the variables

-2x+11

Back to the equation:

-(-2x+11)



We get rid of parentheses

4x+2x-11+8=0

We add all the numbers together, and all the variables

6x-3=0

We move all terms containing x to the left, all other terms to the right

6x=3

x=3/6

x=1/2

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