4(x+2)=6+-2(1-x)

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Solution for 4(x+2)=6+-2(1-x) equation: 



4(x+2)=6+-2(1-x)

We move all terms to the left:

4(x+2)-(6+-2(1-x))=0

We add all the numbers together, and all the variables

4(x+2)-(6+-2(-1x+1))=0

We use the square of the difference formula

4(x+2)-(6-2(-1x+1))=0

We multiply parentheses

4x-(6-2(-1x+1))+8=0



We calculate terms in parentheses: -(6-2(-1x+1)), so:

6-2(-1x+1)

determiningTheFunctionDomain
-2(-1x+1)+6

We multiply parentheses

2x-2+6

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

4x-2x-4+8=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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