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4(x+2)=6-2(2x+1)
We move all terms to the left:
4(x+2)-(6-2(2x+1))=0
We multiply parentheses
4x-(6-2(2x+1))+8=0
We calculate terms in parentheses: -(6-2(2x+1)), so:We get rid of parentheses
6-2(2x+1)
determiningTheFunctionDomain -2(2x+1)+6
We multiply parentheses
-4x-2+6
We add all the numbers together, and all the variables
-4x+4
Back to the equation:
-(-4x+4)
4x+4x-4+8=0
We add all the numbers together, and all the variables
8x+4=0
We move all terms containing x to the left, all other terms to the right
8x=-4
x=-4/8
x=-1/2
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