4(x+2)=7(6+3x)

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Solution for 4(x+2)=7(6+3x) equation: 



4(x+2)=7(6+3x)

We move all terms to the left:

4(x+2)-(7(6+3x))=0

We add all the numbers together, and all the variables

4(x+2)-(7(3x+6))=0

We multiply parentheses

4x-(7(3x+6))+8=0



We calculate terms in parentheses: -(7(3x+6)), so:

7(3x+6)

We multiply parentheses

21x+42

Back to the equation:

-(21x+42)



We get rid of parentheses

4x-21x-42+8=0

We add all the numbers together, and all the variables

-17x-34=0

We move all terms containing x to the left, all other terms to the right

-17x=34

x=34/-17

x=-2

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