4(x+2)=7(x+1)

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Solution for 4(x+2)=7(x+1) equation:



4(x+2)=7(x+1)
We move all terms to the left:
4(x+2)-(7(x+1))=0
We multiply parentheses
4x-(7(x+1))+8=0
We calculate terms in parentheses: -(7(x+1)), so:
7(x+1)
We multiply parentheses
7x+7
Back to the equation:
-(7x+7)
We get rid of parentheses
4x-7x-7+8=0
We add all the numbers together, and all the variables
-3x+1=0
We move all terms containing x to the left, all other terms to the right
-3x=-1
x=-1/-3
x=1/3

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