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4(x+3)(3x-2)=576
We move all terms to the left:
4(x+3)(3x-2)-(576)=0
We multiply parentheses ..
4(+3x^2-2x+9x-6)-576=0
We multiply parentheses
12x^2-8x+36x-24-576=0
We add all the numbers together, and all the variables
12x^2+28x-600=0
a = 12; b = 28; c = -600;
Δ = b2-4ac
Δ = 282-4·12·(-600)
Δ = 29584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{29584}=172$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-172}{2*12}=\frac{-200}{24} =-8+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+172}{2*12}=\frac{144}{24} =6 $
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