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4(x+3)(5x-2)=0
We multiply parentheses ..
4(+5x^2-2x+15x-6)=0
We multiply parentheses
20x^2-8x+60x-24=0
We add all the numbers together, and all the variables
20x^2+52x-24=0
a = 20; b = 52; c = -24;
Δ = b2-4ac
Δ = 522-4·20·(-24)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-68}{2*20}=\frac{-120}{40} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+68}{2*20}=\frac{16}{40} =2/5 $
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