4(x+3)+(x+3)+x=33

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Solution for 4(x+3)+(x+3)+x=33 equation: 



4(x+3)+(x+3)+x=33

We move all terms to the left:

4(x+3)+(x+3)+x-(33)=0

We add all the numbers together, and all the variables

x+4(x+3)+(x+3)-33=0

We multiply parentheses

x+4x+(x+3)+12-33=0

We get rid of parentheses

x+4x+x+3+12-33=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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