4(x+3)+12=3(x+4)+11

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Solution for 4(x+3)+12=3(x+4)+11 equation: 



4(x+3)+12=3(x+4)+11

We move all terms to the left:

4(x+3)+12-(3(x+4)+11)=0

We multiply parentheses

4x-(3(x+4)+11)+12+12=0



We calculate terms in parentheses: -(3(x+4)+11), so:

3(x+4)+11

We multiply parentheses

3x+12+11

We add all the numbers together, and all the variables

3x+23

Back to the equation:

-(3x+23)



We add all the numbers together, and all the variables

4x-(3x+23)+24=0

We get rid of parentheses

4x-3x-23+24=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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