4(x+3)+18-x=2(-x+5)+5(2-x)

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Solution for 4(x+3)+18-x=2(-x+5)+5(2-x) equation: 



4(x+3)+18-x=2(-x+5)+5(2-x)

We move all terms to the left:

4(x+3)+18-x-(2(-x+5)+5(2-x))=0

We add all the numbers together, and all the variables

4(x+3)-x-(2(-1x+5)+5(-1x+2))+18=0

We add all the numbers together, and all the variables

-1x+4(x+3)-(2(-1x+5)+5(-1x+2))+18=0

We multiply parentheses

-1x+4x-(2(-1x+5)+5(-1x+2))+12+18=0



We calculate terms in parentheses: -(2(-1x+5)+5(-1x+2)), so:

2(-1x+5)+5(-1x+2)

We multiply parentheses

-2x-5x+10+10

We add all the numbers together, and all the variables

-7x+20

Back to the equation:

-(-7x+20)



We add all the numbers together, and all the variables

3x-(-7x+20)+30=0

We get rid of parentheses

3x+7x-20+30=0

We add all the numbers together, and all the variables

10x+10=0

We move all terms containing x to the left, all other terms to the right

10x=-10

x=-10/10

x=-1

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