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4(x+3)+2((x+4)-7=7(x+8)+5(x+3)+2
We move all terms to the left:
4(x+3)+2((x+4)-7-(7(x+8)+5(x+3)+2)=0
We multiply parentheses
4x+2((x+4)-7-(7(x+8)+5(x+3)+2)+12=0
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