4(x+3)+2(6x-4)=8

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Solution for 4(x+3)+2(6x-4)=8 equation:



4(x+3)+2(6x-4)=8
We move all terms to the left:
4(x+3)+2(6x-4)-(8)=0
We multiply parentheses
4x+12x+12-8-8=0
We add all the numbers together, and all the variables
16x-4=0
We move all terms containing x to the left, all other terms to the right
16x=4
x=4/16
x=1/4

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