4(x+3)+2x=3(3x-4)+3

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Solution for 4(x+3)+2x=3(3x-4)+3 equation:



4(x+3)+2x=3(3x-4)+3
We move all terms to the left:
4(x+3)+2x-(3(3x-4)+3)=0
We add all the numbers together, and all the variables
2x+4(x+3)-(3(3x-4)+3)=0
We multiply parentheses
2x+4x-(3(3x-4)+3)+12=0
We calculate terms in parentheses: -(3(3x-4)+3), so:
3(3x-4)+3
We multiply parentheses
9x-12+3
We add all the numbers together, and all the variables
9x-9
Back to the equation:
-(9x-9)
We add all the numbers together, and all the variables
6x-(9x-9)+12=0
We get rid of parentheses
6x-9x+9+12=0
We add all the numbers together, and all the variables
-3x+21=0
We move all terms containing x to the left, all other terms to the right
-3x=-21
x=-21/-3
x=+7

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