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4(x+3)+3(2-x)=10
We move all terms to the left:
4(x+3)+3(2-x)-(10)=0
We add all the numbers together, and all the variables
4(x+3)+3(-1x+2)-10=0
We multiply parentheses
4x-3x+12+6-10=0
We add all the numbers together, and all the variables
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8
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