4(x+3)+3(x-2)=41

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Solution for 4(x+3)+3(x-2)=41 equation: 



4(x+3)+3(x-2)=41

We move all terms to the left:

4(x+3)+3(x-2)-(41)=0

We multiply parentheses

4x+3x+12-6-41=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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