4(x+3)+3=7x+12

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Solution for 4(x+3)+3=7x+12 equation: 



4(x+3)+3=7x+12

We move all terms to the left:

4(x+3)+3-(7x+12)=0

We multiply parentheses

4x-(7x+12)+12+3=0

We get rid of parentheses

4x-7x-12+12+3=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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