4(x+3)+3x=7(x-2)

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Solution for 4(x+3)+3x=7(x-2) equation:


Simplifying
4(x + 3) + 3x = 7(x + -2)

Reorder the terms:
4(3 + x) + 3x = 7(x + -2)
(3 * 4 + x * 4) + 3x = 7(x + -2)
(12 + 4x) + 3x = 7(x + -2)

Combine like terms: 4x + 3x = 7x
12 + 7x = 7(x + -2)

Reorder the terms:
12 + 7x = 7(-2 + x)
12 + 7x = (-2 * 7 + x * 7)
12 + 7x = (-14 + 7x)

Add '-7x' to each side of the equation.
12 + 7x + -7x = -14 + 7x + -7x

Combine like terms: 7x + -7x = 0
12 + 0 = -14 + 7x + -7x
12 = -14 + 7x + -7x

Combine like terms: 7x + -7x = 0
12 = -14 + 0
12 = -14

Solving
12 = -14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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