4(x+3)+4=5(x-2)+5

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Solution for 4(x+3)+4=5(x-2)+5 equation: 



4(x+3)+4=5(x-2)+5

We move all terms to the left:

4(x+3)+4-(5(x-2)+5)=0

We multiply parentheses

4x-(5(x-2)+5)+12+4=0



We calculate terms in parentheses: -(5(x-2)+5), so:

5(x-2)+5

We multiply parentheses

5x-10+5

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We add all the numbers together, and all the variables

4x-(5x-5)+16=0

We get rid of parentheses

4x-5x+5+16=0

We add all the numbers together, and all the variables

-1x+21=0

We move all terms containing x to the left, all other terms to the right

-x=-21

x=-21/-1

x=+21

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