4(x+3)+5(3x-8)=12-2(3x+1)

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Solution for 4(x+3)+5(3x-8)=12-2(3x+1) equation: 



4(x+3)+5(3x-8)=12-2(3x+1)

We move all terms to the left:

4(x+3)+5(3x-8)-(12-2(3x+1))=0

We multiply parentheses

4x+15x-(12-2(3x+1))+12-40=0



We calculate terms in parentheses: -(12-2(3x+1)), so:

12-2(3x+1)

determiningTheFunctionDomain
-2(3x+1)+12

We multiply parentheses

-6x-2+12

We add all the numbers together, and all the variables

-6x+10

Back to the equation:

-(-6x+10)



We add all the numbers together, and all the variables

19x-(-6x+10)-28=0

We get rid of parentheses

19x+6x-10-28=0

We add all the numbers together, and all the variables

25x-38=0

We move all terms containing x to the left, all other terms to the right

25x=38

x=38/25

x=1+13/25

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