4(x+3)+6(x-2)=140

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Solution for 4(x+3)+6(x-2)=140 equation: 



4(x+3)+6(x-2)=140

We move all terms to the left:

4(x+3)+6(x-2)-(140)=0

We multiply parentheses

4x+6x+12-12-140=0

We add all the numbers together, and all the variables

10x-140=0

We move all terms containing x to the left, all other terms to the right

10x=140

x=140/10

x=14

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