4(x+3)+6=7(x+2)

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Solution for 4(x+3)+6=7(x+2) equation: 



4(x+3)+6=7(x+2)

We move all terms to the left:

4(x+3)+6-(7(x+2))=0

We multiply parentheses

4x-(7(x+2))+12+6=0



We calculate terms in parentheses: -(7(x+2)), so:

7(x+2)

We multiply parentheses

7x+14

Back to the equation:

-(7x+14)



We add all the numbers together, and all the variables

4x-(7x+14)+18=0

We get rid of parentheses

4x-7x-14+18=0

We add all the numbers together, and all the variables

-3x+4=0

We move all terms containing x to the left, all other terms to the right

-3x=-4

x=-4/-3

x=1+1/3

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