4(x+3)+x=2(x+3)+7

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Solution for 4(x+3)+x=2(x+3)+7 equation: 



4(x+3)+x=2(x+3)+7

We move all terms to the left:

4(x+3)+x-(2(x+3)+7)=0

We add all the numbers together, and all the variables

x+4(x+3)-(2(x+3)+7)=0

We multiply parentheses

x+4x-(2(x+3)+7)+12=0



We calculate terms in parentheses: -(2(x+3)+7), so:

2(x+3)+7

We multiply parentheses

2x+6+7

We add all the numbers together, and all the variables

2x+13

Back to the equation:

-(2x+13)



We add all the numbers together, and all the variables

5x-(2x+13)+12=0

We get rid of parentheses

5x-2x-13+12=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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