4(x+3)-10=6(x-2)=

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Solution for 4(x+3)-10=6(x-2)= equation: 



4(x+3)-10=6(x-2)=

We move all terms to the left:

4(x+3)-10-(6(x-2))=0

We multiply parentheses

4x-(6(x-2))+12-10=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

4x-(6x-12)+2=0

We get rid of parentheses

4x-6x+12+2=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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