4(x+3)-18=2(x-7)+36

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Solution for 4(x+3)-18=2(x-7)+36 equation: 



4(x+3)-18=2(x-7)+36

We move all terms to the left:

4(x+3)-18-(2(x-7)+36)=0

We multiply parentheses

4x-(2(x-7)+36)+12-18=0



We calculate terms in parentheses: -(2(x-7)+36), so:

2(x-7)+36

We multiply parentheses

2x-14+36

We add all the numbers together, and all the variables

2x+22

Back to the equation:

-(2x+22)



We add all the numbers together, and all the variables

4x-(2x+22)-6=0

We get rid of parentheses

4x-2x-22-6=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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