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4(x+3)-4=4(x+1)
We move all terms to the left:
4(x+3)-4-(4(x+1))=0
We multiply parentheses
4x-(4(x+1))+12-4=0
We calculate terms in parentheses: -(4(x+1)), so:We add all the numbers together, and all the variables
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
4x-(4x+4)+8=0
We get rid of parentheses
4x-4x-4+8=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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