4(x+3)-4=8((1/2)x+1)

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Solution for 4(x+3)-4=8((1/2)x+1) equation:



4(x+3)-4=8((1/2)x+1)
We move all terms to the left:
4(x+3)-4-(8((1/2)x+1))=0
Domain of the equation: 2)x+1))!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
4(x+3)-(8((+1/2)x+1))-4=0
We multiply parentheses
4x-(8((+1/2)x+1))+12-4=0
We multiply all the terms by the denominator
4x*2)x+1))-(8((+12*2)x+1))-4*2)x+1))+1=0
We add all the numbers together, and all the variables
4x*2)x+1))-(8(24x+1))-4*2)x+1))+1=0
Wy multiply elements
16x^3=0
We do not support expression: x^3

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