4(x+3)-4=8(1/2x)+1

Solution for 4(x+3)-4=8(1/2x)+1 equation:

4(x+3)-4=8(1/2x)+1

We move all terms to the left:

4(x+3)-4-(8(1/2x)+1)=0


Domain of the equation: 2x)+1)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4(x+3)-(8(+1/2x)+1)-4=0

We multiply parentheses

4x-(8(+1/2x)+1)+12-4=0

We multiply all the terms by the denominator


4x*2x)+1)-(8(+12*2x)+1)-4*2x)+1)+1=0

Wy multiply elements

8x^2+48x^2=0

We add all the numbers together, and all the variables

56x^2=0

a = 56; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·56·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{112}=0$