4(x+3)-4=8(1/2x+10

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Solution for 4(x+3)-4=8(1/2x+10 equation: 



4(x+3)-4=8(1/2x+10

We move all terms to the left:

4(x+3)-4-(8(1/2x+10)=0



Domain of the equation: 2x+10)-4!=0

x∈R



We multiply parentheses

4x-(8(1/2x+10)-4+12=0

We multiply all the terms by the denominator


4x*2x+10)-4+12-(8(1=0

We add all the numbers together, and all the variables

4x*2x=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$

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