4(x+3)-5=6x-2(-5+x)

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Solution for 4(x+3)-5=6x-2(-5+x) equation: 



4(x+3)-5=6x-2(-5+x)

We move all terms to the left:

4(x+3)-5-(6x-2(-5+x))=0

We add all the numbers together, and all the variables

4(x+3)-(6x-2(x-5))-5=0

We multiply parentheses

4x-(6x-2(x-5))+12-5=0



We calculate terms in parentheses: -(6x-2(x-5)), so:

6x-2(x-5)

We multiply parentheses

6x-2x+10

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We add all the numbers together, and all the variables

4x-(4x+10)+7=0

We get rid of parentheses

4x-4x-10+7=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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