4(x+3)-7x=5(2-x)+18

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Solution for 4(x+3)-7x=5(2-x)+18 equation: 



4(x+3)-7x=5(2-x)+18

We move all terms to the left:

4(x+3)-7x-(5(2-x)+18)=0

We add all the numbers together, and all the variables

4(x+3)-7x-(5(-1x+2)+18)=0

We add all the numbers together, and all the variables

-7x+4(x+3)-(5(-1x+2)+18)=0

We multiply parentheses

-7x+4x-(5(-1x+2)+18)+12=0



We calculate terms in parentheses: -(5(-1x+2)+18), so:

5(-1x+2)+18

We multiply parentheses

-5x+10+18

We add all the numbers together, and all the variables

-5x+28

Back to the equation:

-(-5x+28)



We add all the numbers together, and all the variables

-3x-(-5x+28)+12=0

We get rid of parentheses

-3x+5x-28+12=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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