4(x+3)-8(6x-4)=16

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Solution for 4(x+3)-8(6x-4)=16 equation:



4(x+3)-8(6x-4)=16
We move all terms to the left:
4(x+3)-8(6x-4)-(16)=0
We multiply parentheses
4x-48x+12+32-16=0
We add all the numbers together, and all the variables
-44x+28=0
We move all terms containing x to the left, all other terms to the right
-44x=-28
x=-28/-44
x=7/11

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