4(x+3)-8=2(x+3)+3x

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Solution for 4(x+3)-8=2(x+3)+3x equation: 



4(x+3)-8=2(x+3)+3x

We move all terms to the left:

4(x+3)-8-(2(x+3)+3x)=0

We multiply parentheses

4x-(2(x+3)+3x)+12-8=0



We calculate terms in parentheses: -(2(x+3)+3x), so:

2(x+3)+3x

We add all the numbers together, and all the variables

3x+2(x+3)

We multiply parentheses

3x+2x+6

We add all the numbers together, and all the variables

5x+6

Back to the equation:

-(5x+6)



We add all the numbers together, and all the variables

4x-(5x+6)+4=0

We get rid of parentheses

4x-5x-6+4=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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