4(x+3)-8=3(x+2)+x

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Solution for 4(x+3)-8=3(x+2)+x equation: 


Simplifying
4(x + 3) + -8 = 3(x + 2) + x

Reorder the terms:
4(3 + x) + -8 = 3(x + 2) + x
(3 * 4 + x * 4) + -8 = 3(x + 2) + x
(12 + 4x) + -8 = 3(x + 2) + x

Reorder the terms:
12 + -8 + 4x = 3(x + 2) + x

Combine like terms: 12 + -8 = 4
4 + 4x = 3(x + 2) + x

Reorder the terms:
4 + 4x = 3(2 + x) + x
4 + 4x = (2 * 3 + x * 3) + x
4 + 4x = (6 + 3x) + x

Combine like terms: 3x + x = 4x
4 + 4x = 6 + 4x

Add '-4x' to each side of the equation.
4 + 4x + -4x = 6 + 4x + -4x

Combine like terms: 4x + -4x = 0
4 + 0 = 6 + 4x + -4x
4 = 6 + 4x + -4x

Combine like terms: 4x + -4x = 0
4 = 6 + 0
4 = 6

Solving
4 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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