4(x+3)-8x=3(x+2)=x

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Solution for 4(x+3)-8x=3(x+2)=x equation: 



4(x+3)-8x=3(x+2)=x

We move all terms to the left:

4(x+3)-8x-(3(x+2))=0

We add all the numbers together, and all the variables

-8x+4(x+3)-(3(x+2))=0

We multiply parentheses

-8x+4x-(3(x+2))+12=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-4x-(3x+6)+12=0

We get rid of parentheses

-4x-3x-6+12=0

We add all the numbers together, and all the variables

-7x+6=0

We move all terms containing x to the left, all other terms to the right

-7x=-6

x=-6/-7

x=6/7

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