4(x+3)-9x=3(x+2)+x

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Solution for 4(x+3)-9x=3(x+2)+x equation: 



4(x+3)-9x=3(x+2)+x

We move all terms to the left:

4(x+3)-9x-(3(x+2)+x)=0

We add all the numbers together, and all the variables

-9x+4(x+3)-(3(x+2)+x)=0

We multiply parentheses

-9x+4x-(3(x+2)+x)+12=0



We calculate terms in parentheses: -(3(x+2)+x), so:

3(x+2)+x

We add all the numbers together, and all the variables

x+3(x+2)

We multiply parentheses

x+3x+6

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

-5x-(4x+6)+12=0

We get rid of parentheses

-5x-4x-6+12=0

We add all the numbers together, and all the variables

-9x+6=0

We move all terms containing x to the left, all other terms to the right

-9x=-6

x=-6/-9

x=2/3

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