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4(x+3)/5=x-3
We move all terms to the left:
4(x+3)/5-(x-3)=0
We get rid of parentheses
4(x+3)/5-x+3=0
We multiply all the terms by the denominator
4(x+3)-x*5+3*5=0
We add all the numbers together, and all the variables
4(x+3)-x*5+15=0
We multiply parentheses
4x-x*5+12+15=0
Wy multiply elements
4x-5x+12+15=0
We add all the numbers together, and all the variables
-1x+27=0
We move all terms containing x to the left, all other terms to the right
-x=-27
x=-27/-1
x=+27
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