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4(x+3)=2(2x-2)
We move all terms to the left:
4(x+3)-(2(2x-2))=0
We multiply parentheses
4x-(2(2x-2))+12=0
We calculate terms in parentheses: -(2(2x-2)), so:We get rid of parentheses
2(2x-2)
We multiply parentheses
4x-4
Back to the equation:
-(4x-4)
4x-4x+4+12=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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