4(x+3)=2(x+4)+2(x+1)

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Solution for 4(x+3)=2(x+4)+2(x+1) equation: 



4(x+3)=2(x+4)+2(x+1)

We move all terms to the left:

4(x+3)-(2(x+4)+2(x+1))=0

We multiply parentheses

4x-(2(x+4)+2(x+1))+12=0



We calculate terms in parentheses: -(2(x+4)+2(x+1)), so:

2(x+4)+2(x+1)

We multiply parentheses

2x+2x+8+2

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

4x-4x-10+12=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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