4(x+3)=2(x-1)+3(x+1)

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Solution for 4(x+3)=2(x-1)+3(x+1) equation: 



4(x+3)=2(x-1)+3(x+1)

We move all terms to the left:

4(x+3)-(2(x-1)+3(x+1))=0

We multiply parentheses

4x-(2(x-1)+3(x+1))+12=0



We calculate terms in parentheses: -(2(x-1)+3(x+1)), so:

2(x-1)+3(x+1)

We multiply parentheses

2x+3x-2+3

We add all the numbers together, and all the variables

5x+1

Back to the equation:

-(5x+1)



We get rid of parentheses

4x-5x-1+12=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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