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4(x+3)=2(x-4)
We move all terms to the left:
4(x+3)-(2(x-4))=0
We multiply parentheses
4x-(2(x-4))+12=0
We calculate terms in parentheses: -(2(x-4)), so:We get rid of parentheses
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
4x-2x+8+12=0
We add all the numbers together, and all the variables
2x+20=0
We move all terms containing x to the left, all other terms to the right
2x=-20
x=-20/2
x=-10
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