4(x+3)=3(3x-1)+x

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Solution for 4(x+3)=3(3x-1)+x equation: 



4(x+3)=3(3x-1)+x

We move all terms to the left:

4(x+3)-(3(3x-1)+x)=0

We multiply parentheses

4x-(3(3x-1)+x)+12=0



We calculate terms in parentheses: -(3(3x-1)+x), so:

3(3x-1)+x

We add all the numbers together, and all the variables

x+3(3x-1)

We multiply parentheses

x+9x-3

We add all the numbers together, and all the variables

10x-3

Back to the equation:

-(10x-3)



We get rid of parentheses

4x-10x+3+12=0

We add all the numbers together, and all the variables

-6x+15=0

We move all terms containing x to the left, all other terms to the right

-6x=-15

x=-15/-6

x=2+1/2

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