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4(x+3)=3(x-10)+x+18
We move all terms to the left:
4(x+3)-(3(x-10)+x+18)=0
We multiply parentheses
4x-(3(x-10)+x+18)+12=0
We calculate terms in parentheses: -(3(x-10)+x+18), so:We get rid of parentheses
3(x-10)+x+18
We add all the numbers together, and all the variables
x+3(x-10)+18
We multiply parentheses
x+3x-30+18
We add all the numbers together, and all the variables
4x-12
Back to the equation:
-(4x-12)
4x-4x+12+12=0
We add all the numbers together, and all the variables
24!=0
There is no solution for this equation
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