4(x+3)=4-2(x+2)

Solution for 4(x+3)=4-2(x+2) equation:

4(x+3)=4-2(x+2)

We move all terms to the left:

4(x+3)-(4-2(x+2))=0

We multiply parentheses

4x-(4-2(x+2))+12=0


We calculate terms in parentheses: -(4-2(x+2)), so:

4-2(x+2)

determiningTheFunctionDomain
-2(x+2)+4

We multiply parentheses

-2x-4+4

We add all the numbers together, and all the variables

-2x

Back to the equation:

-(-2x)


We get rid of parentheses

4x+2x+12=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2