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4(x+3)=4x+12-8x
We move all terms to the left:
4(x+3)-(4x+12-8x)=0
We add all the numbers together, and all the variables
4(x+3)-(-4x+12)=0
We multiply parentheses
4x-(-4x+12)+12=0
We get rid of parentheses
4x+4x-12+12=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0
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