4(x+3)=6(x-2)-6

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Solution for 4(x+3)=6(x-2)-6 equation: 



4(x+3)=6(x-2)-6

We move all terms to the left:

4(x+3)-(6(x-2)-6)=0

We multiply parentheses

4x-(6(x-2)-6)+12=0



We calculate terms in parentheses: -(6(x-2)-6), so:

6(x-2)-6

We multiply parentheses

6x-12-6

We add all the numbers together, and all the variables

6x-18

Back to the equation:

-(6x-18)



We get rid of parentheses

4x-6x+18+12=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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