4(x+3)=7(x+2)+7

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Solution for 4(x+3)=7(x+2)+7 equation: 



4(x+3)=7(x+2)+7

We move all terms to the left:

4(x+3)-(7(x+2)+7)=0

We multiply parentheses

4x-(7(x+2)+7)+12=0



We calculate terms in parentheses: -(7(x+2)+7), so:

7(x+2)+7

We multiply parentheses

7x+14+7

We add all the numbers together, and all the variables

7x+21

Back to the equation:

-(7x+21)



We get rid of parentheses

4x-7x-21+12=0

We add all the numbers together, and all the variables

-3x-9=0

We move all terms containing x to the left, all other terms to the right

-3x=9

x=9/-3

x=-3

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