4(x+3)=7(x-4)-x.

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Solution for 4(x+3)=7(x-4)-x. equation: 



4(x+3)=7(x-4)-x.

We move all terms to the left:

4(x+3)-(7(x-4)-x.)=0

We multiply parentheses

4x-(7(x-4)-x.)+12=0



We calculate terms in parentheses: -(7(x-4)-x.), so:

7(x-4)-x.

We multiply parentheses

7x-x.-28

Back to the equation:

-(7x-x.-28)



We get rid of parentheses

4x-7x+x.+28+12=0

We add all the numbers together, and all the variables

-3x+x.+40=0

We move all terms containing x to the left, all other terms to the right

-3x+x.=-40

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