4(x+3)=7-x+20

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Solution for 4(x+3)=7-x+20 equation: 



4(x+3)=7-x+20

We move all terms to the left:

4(x+3)-(7-x+20)=0

We add all the numbers together, and all the variables

4(x+3)-(-1x+27)=0

We multiply parentheses

4x-(-1x+27)+12=0

We get rid of parentheses

4x+1x-27+12=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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