4(x+3)=8(6-x)

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Solution for 4(x+3)=8(6-x) equation: 



4(x+3)=8(6-x)

We move all terms to the left:

4(x+3)-(8(6-x))=0

We add all the numbers together, and all the variables

4(x+3)-(8(-1x+6))=0

We multiply parentheses

4x-(8(-1x+6))+12=0



We calculate terms in parentheses: -(8(-1x+6)), so:

8(-1x+6)

We multiply parentheses

-8x+48

Back to the equation:

-(-8x+48)



We get rid of parentheses

4x+8x-48+12=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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